8v^2+96v-104=0

Solution for 8v^2+96v-104=0 equation:

8v^2+96v-104=0

a = 8; b = 96; c = -104;
Δ = b2-4ac
Δ = 962-4·8·(-104)
Δ = 12544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12544}=112$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(96)-112}{2*8}=\frac{-208}{16}
=-13
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(96)+112}{2*8}=\frac{16}{16}
=1
$